Concave lenses are characterized by their curved-inward shape. When light rays pass through a concave lens, they diverge (spread out). Here are some key points about concave lenses:
Focal Length:
The focal length of a concave lens is always negative.
It represents the distance from the lens to the point where parallel rays converge (or appear to converge) after passing through the lens.
In your case, the focal length is given as 10 cm.
Image Formation:
When an object is placed in front of a concave lens, the following scenarios can occur:
If the object is at infinity (very far away), a virtual, highly diminished image is formed at the focus.
If the object is beyond the center of curvature, a real, diminished image is formed between the center of curvature and the focus.
If the object is at the center of curvature, a real, same-sized image is formed at the other center of curvature.
If the object is between the center of curvature and the focus, a real, enlarged image is formed behind the center of curvature.
If the object is at the focus itself, a real, highly enlarged image is formed at infinity.
If the object is between the focus and the optical center, a virtual, enlarged image is formed.
Lens Formula:
The lens formula relates the object distance ((u)), image distance ((v)), and focal length ((f)) of a lens: [ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} ]
Given that the focal length ((f)) of your concave lens is -15 cm and the image distance ((v)) is -10 cm, we can find the object distance ((u)): [ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} ] [ \frac{1}{(-15)} = \frac{1}{(-10)} - \frac{1}{u} ] Solving for (u): [ \frac{1}{u} = \frac{1}{10} - \frac{1}{15} ] [ \frac{1}{u} = \frac{2}{30} ] [ u = -30 , \text{cm} ]
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